How many sodium ions in 2.00 mol of nacl

1.20 x 10^24

Explanation:

This question seeks to test the understanding of mole concept where the number of particles (ions, atoms or subatomic particles) in one mole of any substance is equal to avogadro's number (6.02 x 10^23).

1 mole of NaCl will dissociate in a solution as follow

NaCl →Na+ + Cl-

Hence, 2 moles of NaCl will dissociate as follow

2NaCl → 2Na+ + Cl-

From the above, 2 moles of NaCl will dissociate to give 2 moles of sodium ion (Na+)

The number particles present in 2 moles of Na+ is

2 x 6.02 x 10^23 = 1.2 x 10^24

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products