How many liters at STP are in 8.0 x 102 grams of sulfur dioxide?

280 liters at STP are in 8.0*10² grams of sulfur dioxide.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

In this case, the molar mass of sulfur dioxide, that is, the mass of one mole of the substance, is 64 g/mole.

You can apply the following rule of three: if by definition of molar mass 64 grams of sulfur dioxide are contained in 1 mole, 8.0*10² grams are contained in how many moles?

amount of moles= 12.5 moles

Now you can apply a new rule of three: if by STP conditions 1 mole of any gas occupies a volume of 22.4 liters, 12.5 moles will occupy how much volume?

volume= 280 L

280 liters at STP are in 8.0*10² grams of sulfur dioxide.

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.