Use the graph to answer these questions. 6CO2(g) + 6H2O(g)
C&H 206(s) + 602(g)
The total energy of the products is
O -3,811.92 kJ.
CH1206(s) + O2(g
с
O
-1,273.02 kJ
-1273.02 kJ
-2,538.90 kJ.
DO NE
Energy
A
B
-3811.92 kJ
6CO2(g) + 6H2O(g)
Reaction Progression

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o