How much of 1.0 g would be left after 3 half lives​

0.125 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 1 g

Number of half-lives (n) = 3

Amount remaining (N) =?

We can obtain the amount of the substance remaining by using the following formula:

N = 1/2ⁿ × N₀

N = 1/2³ × 1

N = ⅛ × 1

N = 0.125 × 1

N = 0.125 g

Thus, 0.125 g of the substance will remain after 3 half-lives.

h let me think

- "the acute form of diverticulitis can manifest itself with one or more severe attacks of infection and inflammation.

the inflammation of diverticulitis can eventually result in a bowel obstruction, which may cause constipation, thin stools, diarrhea, abdominal swelling or bloating, and abdominal pain."