0.75 moles of an unknown acid are dissolved in water. If 0.42 moles of H3O+ form, what was the percent dissociation of the unknown acid?

56 %

Explanation:

The percent dissociation of a weak acid can be defined as:

Moles of weak acid that produced H₃O⁺ species / Total number of weak acid moles * 100%

We are given all the required data to calculate the percent dissociation:

0.42 mol / 0.75 mol * 100 % = 56 %

The percent dissociation is 56%.

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

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