How many milliliter of 3.0 M H2SO4 are needed to make 450.0 mL of 0.20 M H2SO4?

 97.2223 ml

Explanation:

The rule that we will use to solve this problem is:

M2*V1 = M2*V2 where:

M1 is the initial concentration = 3.5 m

V1 is the initial volume = 0.25 l = 250 ml

M2 is the final concentration = 9 m

V2 is the final volume that we need to find

Substitute with the givens in the above equation to get V2 as follows:

3.5*250 = 9*V2

V2 = 97.2223 ml

Explanation:

it's c (engineer's do their work with mechanical stuff not on any living being)