What volume in
L
of a 0.724 M Nal solution contains 0.405 mol of Nal ?

0.559 L

Explanation:

Step 1: Given data

Moles of sodium iodide (n): 0.405 mol

Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V  

V = n/M  

V = 0.405 mol/(0.724 mol/L) = 0.559 L

(hope this helps can i plz have brainlist :D hehe)

lol idk man i guess u gotta ask bill nye the science guy