Question 1: How many atoms are in 25.00 g of Li.
A. 2.393 x 10^24 atoms of Li
B. 1.333 x 10^23 atoms of Li
C. 2.16 x 10^26 atoms of Li
D. 2.17 x 10^24 atoms of Li
Question 2:
How many grams is 2.393 x 10^24 atoms of CI
A. 70.45 g CI
B. 140.9 g CI
C. 140.9 mole CI
D. 70.45 mole CI
Please try to answer both questions! Thanks for all the effort :)

1.a

2.c

hope helps

Explanation:

mark

pa

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :