You have the following equations: 2S (s) + 3O 2 (g) → 2SO 3 (g), Δ H = –792 kJ
2S (s) + 2O 2 (g) → 2SO 2 (g), Δ H = –594 kJ
2SO 2 (g) + O 2 (g) → 2SO 3 (g), Δ H = ?

What is the missing ΔH?

Question options:

+198 kJ

–198 kJ

–294 kJ

+294 kJ

i don,t know so just answer mine

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

i'm wiling to try and you : )

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.