A student did not read the directions to the experiment properly and mixed up where to place the NaOH solution and the vinegar. He put the vinegar in the titrator and the measured amount of NaOH in the beaker. He then added a drop of the phenolphthalein to the solution in the beaker. Does the student need to empty out all of the solutions and start over again or can he go ahead and run the titration? If he runs the titration using the solutions as given above, what should he expect to see happen for results?

The answer is "Only at the end, a transformation of rose to color is made ".

Explanation:

 In this student puts its vinegar in the titrator, and NaOH throughout the beaker, which implies phenolphthalein has also been poured into water.

Phenolphthalein does have a pH range of 8.3-10 (approx). It's indeed pink in the basic medium therefore, the formulation becomes pink throughout the color by adding phenolphthalein to NaOH.

It is beginning of vinegar was its beginning of neutralization of NaOH from the titrator through full neutralization, a single piece of vinegar is added to a solution as well as the rose solution is lost throughout the beaker.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023