Chemistry, 08.04.2021 23:40 bleesedbeme
Na2SiO3 (s) + 8 HF (aq) H2SiF6 (aq) + 2 NaF(aq) + 3H2O (l)
1. How many moles of HF are need to react with 0.600 mol of Na2SiO3?
2. How many grams of NaF form when 0.800 mol of HF reacts with excess Na2SiO3?
3. How many grams of Na2SiO3 can react with 0.900 g of HF?
Answers: 3
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Calculate: select the worksheet tab. this tab you calculate the analyte concentration. fill in the first set of boxes ("moles h2so4" and "moles naoh") based on the coefficients in the balanced equation. (if there is no coefficient, the value is 1.) record the appropriate volumes in the "ml naoh" and "ml h2so4" boxes. record the concentration of the titrant in the m naoh box. click calculate. what is the concentration listed
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Acalorimeter is to be calibrated: 51.203 g of water at 55.2 degree c is added to a calorimeter containing 49.783 g of water at 23.5c. after stirring and waiting for the system to equilibrate, the final temperature reached is 37.6 degree c. specific heat capacity of water (s = 4.18 j/g∙degree c). calculate the calorimeter constant. (smδt)warm water = -[(smδt)cold water + (calorimeterδtcold water)]
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Na2SiO3 (s) + 8 HF (aq) H2SiF6 (aq) + 2 NaF(aq) + 3H2O (l)
1. How many moles of HF are need to reac...
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