1. how many grams of each sulphur and oxygen are needed to produce 6.023×10^23 molecules of SO2 according to the reaction:S + O2>SO2.
2.
calculate the no of atoms of C and H in 4 g of methane.​

1.No of moles of SO2=6.022*10^24/AVAGARDOS NUMBER

No of moles=10

1 Moles of So2 contains 1 moles of s and 2 moles of o

10 mole of so2 contains 10 moles of s and 20 moles of o

No of moles of o=weight in gram of o/atomic weight

20*16=Weight =320 kg

And similarly for sulphur(atomic weight32)

2.1.5055x10^23 C atoms and 6.022x10^23 H atoms

Molar Mass of 1 molecule of methane(CH4) = 12 +

4 = 16g/mol =

That is, 16g if CH4 contain 1 mole molecule of it

= 6.022x1023 molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.

=> 4 g of CH4 contains 1/4 x 6.022x1023

molecules

= 1.5055*10^23 molecules of CH4

= 1.5055*10^23 C atoms and 6.022x10^23 H atoms