Phosphorous-32 (P-32) decays to sulfur-32 (S-32) with a half life of 14 days. What fraction of the original amount of P-32 will remain after 42 days? Group of answer choices

1/8 of the original amount

1/2 of the original amount

1/16 of the original amount

1/4 of the original amount

im not exactly sure but i think its b!

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

it takes on an electronical energy

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)