. What would the molarity of the solution be if you had 65.2 grams of Nabu and you dissolved it in exactly 4.00 L of solution?
20 Apressure of 5 atm co bassolubility of 76 At what rescue would its solubility be at 41

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .