Rewrite the following equations and add coefficients in the blanks if the elements in the reaction need to be balanced. 14. ___Mg + ___HCl à ___H2 + MgCl2

15. ___ Al + ___Cl2à ___AlCl3

16. ___Fe + ___H2SO4à ___H2 + ___Fe2(SO4)3

17. CaBr2 + ___Ni2O3à ___NiBr3 + ___ CaO

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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explanation:

2b2t

explanation:

2b2t

i think its 100.

hope this !