A gas sample at 40° C occupies a volume of 3.22 L. If the temperature is raised to 55°C, what will the volume be, assuming the pressure remains constant?

3.374L

Explanation:

According to Charle's Law:

V1/T1=V2/T2 (At constant pressure and moles)

where V=Volume and T=Temperature.

The temperature must be in kelvin.

K=C°+273

T1=40+273=313K

T2=55+273=328K

By applying the formula, we get:

3.22/313=V2/328

V2=(3.22*328)/313

V2=3.374L

they both have a y in them

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