Na, Cosi ) + Pb(NO3)2,
PbCost )
2 NaNO312
)
A. Write the complete (overall) ionic equation for the equation above.
B. Cross out the spectator ions.
C. Write the net ionic equation.

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally