Version: TAKEHOME 1) The ionic compound below is soluble in water. Complete the following:
-Draw the interaction of the ionic compound and water in the proper orientation. 3pts
-On the line below discuss the strength of the interaction within the compound compared to the strength of interaction
between the compound and water.

The hydrogens of the water molecules around the bromide ion will need to be faced toward it, whereas the oxygens of the water molecules around the potassium ion will need to be faced toward it.

The strength of the interaction within the compound will supersede that of the interaction between the compound and water.

Explanation:

To answer this question, you need to be aware of the structure of a water molecule and its components. A water molecule has the chemical formula of H2O, and oxygen is inherently electronegative, meaning that it attracts electrons very strongly. As a result, when it is in H2O, it pulls the valence electrons of the H atoms very strongly, which results  in the H atoms being partially positively charged and the O atom being partially negatively charged. Therefore, the O atom is going to be attracted to the potassium ion, whereas the H atom is going to be attracted to the bromide ion.

The answer to the second part of the question is as written above because ionic bonds are stronger than ion-dipole bonds; that's just the way it is.  

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the answer is minerals.