Mg(s) + 2HCl (aq) > MgCl2 (aq) + H2 You have 6.00 g HCl and 4.8 g Mg.
What is the limiting reaction

HCl is the limiting reactant

Explanation:

To find the limiting reactant of a reaction we must find the moles of each one as follows:

Moles Mg (Molar mass: 24.305g/mol)

4.8g Mg * (qmol / 24.305g) = 0.20 moles Mg

Moles HCl (Molar mass: 36.46g/mol)

6.00g HCl* (1mol / 36.46g) = 0.165 moles HCl

Based on the chemical reaction, for a complete reaction of 0.20 moles of Mg are necessaries:

0.20 moles Mg * (2mol HCl / 1mol Mg) = 0.40 moles HCl

As there are just 0.165 moles of HCl:

the answer is true. hope it .