What is the boiling point of a solution made by dissolving 10.0 g sucrose (C12H22O11) in 500.0 g carbon tetrachloride (CCl4)? The boiling point of carbon tetrachloride is 76.5°C and the boiling point elevation constant, Kb for carbon tetrachloride is 5.03°C/mol.

The question is incomplete. complete question is attached belowanswer: correct answer is option b  i.e.  solid particles  reason: filter paper has small pores, through which smaller particles can pass through. however, solid particles  have relatively larger size. hence, they are least likely to pass through.

Trisulfur dichloridetrisulfur because there are 3 sulfurs & dichloride because there are 2 chloride