Determine the molecular geometry based on the description of bonding and lone pairs of electrons around the central atom. a. Two double bonds and no lone pairs of electrons
b. Six single bonds and no lone pairs of electrons
c. Two single bonds and two lone pairs of electrons
d. Four single bonds and no lone pairs of electrons .
e. Three double bonds and no lone pairs of electrons
f. Five single bonds and no lone pairs of electrons
g. Three single bonds and one lone pair of electrons

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

ok whats the question if not i cannot you i need question and need a thing to answer