150. g of aluminum chloride in 0.450 liters of solution, what is the concentration? (any examples are helpful, thank you)

2.49 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles AlCl₃ (solute)

The molar mass of AlCl₃ is 133.34 g/mol.

150. g × 1 mol/133.34 g = 1.12 mol

Step 3: Calculate the molar concentration of AlCl₃

Molarity is equal to the moles of solute divided by the liters of solution.

M = 1.12 mol/0.450 L = 2.49 M

i think it is true since you can test the answer and can use observations to complete it.

the answer is:  

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