If CH4(g) is at 10 degrees C and 1 atm and has a volume of 10 L, what temperature will it be at when the pressure increases to 3 atm and volume
decreases to 5 L?
A. 15 degrees C
B. 20 degrees C
C. 7 degrees C
D. 110 degrees C

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it's filtration, but this is an assumption so my apologies if i got this

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole