Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial. Trial 1: 0.251Mg/ 1 x 1 mole mg/ 24.305Mg x 2mol MgO/2 mol Mg x 40.304 MgO/ 1 mole MgO=
Trial 2: 0.314Mg/ 1 x 1 mole mg/ 24.305Mg x 2mol MgO/2 mol Mg x 40.304 MgO/ 1 mole MgO=

Achemist 16 drop copper metal from copper chloride solution. the chemist place is 0.50 g of aluminum foil in a solution containing 0.75 g of copper (ii) chloride. a single replacement reaction takes place. which statement explains the maximum amount of copper that the chemist can extract using this reaction?