Chemistry, 24.03.2021 18:30 caudhdi11721
Combustion analysis of a hydrocarbon produced
38.8g of CO2 and 31.7g of H20. Calculate the
empirical formula of the hydrocarbon.
[?]H
[?]
Answers: 2
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .
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How many atoms or molecules are there in a mole of a substance?
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Combustion analysis of a hydrocarbon produced
38.8g of CO2 and 31.7g of H20. Calculate the
em...
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