How many grams of iron are needed to produce 75.0 g of iron(III) chloride?

Explanation:

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In this case, given the chemical reaction:

In such a way, given the volumes and molarities of each reactant, we can compute the moles of produced iron (III) hydroxide by each of them, via the 3:1 and 1:1 mole ratios:

It means that the sodium hydroxide is the limiting reactant and 0.00833 moles of iron (III) hydroxide are produced; thus, the required mass is:

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