In the reaction between ammonia and fluorine shown below 2.643 g of ammonia react with 1.890 g of fluorine. 2NH3(g) + 5F2(g) → N2F4(g) + 6HF(g)

1. The limiting reagent is .
(Convert to grams of N2F4.)
2. if the reaction goes to completion (100% yield), the amount of excess reagent is left over is grams.
3. If the tetrafluorohydrazine (N2F4) is produced in a 75.00% yield, the amount, in grams, that forms is