Tin metal reacts with hydrogen fluoride to produce tin (II) fluoride and hydrogen gas according to the following balanced equation. Sn(s)+ 2HF(g) → SnF₂(s)+H₂(g) How many moles of hydrogen fluoride, HF, are required to react completely with 75.0g of tin? What information are you given?

g of Sn
mol of Sn
mol of HF
g of HF

Explanation is in the file

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the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .