Acompound is 2% h, 32.7% s, and 65.3% o by mass. what is the subscript on the o in the empirical formula for this compound?

The subscrip for O is 4

Explanation:

The first step for this question is to assume that we have 100 g of the unknown compound. If we have 100g then we will have:

2 g of H

32.7 g of S

65.3 g of O

The next step is find the moles for each atom. So, we have to use the molar mass of each atom.

1 g/mol of H

32 g/mol for S

16 g/mol for O

Now, we can find the moles if we divide by the molar mass:

Then we have to divide the smallest mol number, so:

So, the formula would be: with a "4" for oxygen.

answer; /// the amount of material dissolved in a measure of liquid(concentration) the above statement is (true); /// good luck