A 3 L pocket of air at sea level has a pressure of 100 atm. Suppose the air pockets rise in the atmosphere to a certain height and expands to a volume of 10 L. What is the pressure of the air at the new volume?

30 atm

Explanation:

Initial Volume, V1 = 3L

Initial Pressure, P1 = 100 atm

Final Volume V2 = 10 L

Final Pressure, P2 = ?

These quantities are related by the Boyle's law equation which is given as;

V1P1 = V2P2

P2 = V1 * P1  /  V2

P2 = 3 * 100 / 10

P2 = 30 atm

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.