Although some citric acid cycle enzymes operate primarily in the mitochondria, malate dehydrogenase operates in both the cytosol and the mitochondria. Match each function to cytosolic malate dehydrogenase or mitochondrial malate dehydrogenase. A. Cytosolic malate dehydrogenase

B. Mitochontrial malate dehydrogenase

1. transfers reducing equivalents from cytosolic NADH to a molecule that can tranverse the inner mitochondrial membrane

2. generates mitochontrial NADH from reducing equivalents that originate in the cytosol

3. reduces oxaloacetate to malate

4. oxidizes malate to oxaloacetate

5. reduces NAD+ to NADH

6. oxidezes NADH produced in glycosis to NAD+

7. catalyzes last reaction in citric acid cycle that regenrates oxaloacetate( ▲G = 29.7kJ/mol)

The answer is b because c don't explain why the moths are on them and it isn't a because as we know only one species of moth does this

Combustion is the act or process of burning. therefore, i believe the answer is  a: burning wood. 

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

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