Calculate the change in heat (Q) that occurs when 27.58grams of liquid water at 16°C heats to water vapor at 62°C. (cp = 4.184 J/g°C)

5308.16J

Explanation:

Using the formula;

Q = m × cp × ∆T

Where;

Q = change in heat (J)

m = mass of substance (g)

cp = specific heat capacity (4.184 J/g°C)

∆T = change in temperature (°C)

According to the information given in this question;

Q = ?

m = 27.58 grams

cp = 4.184 J/g°C

∆T = 62°C - 16°C = 46°C

Using Q = m × cp × ∆T

Q = 27.58 × 4.184 × 46

Q = 5308.157

Q = 5308.16J

im not exactly sure but i think its b!