Balance each chemical reaction below and identify the reaction type by writing the appropriate abbreviation from the box.
Synthesis
SY
Decomposition DC
Combustion
С
Single Displacement SD
Double Displacement DD
Acid-Base
AB
Balance
Type
1)
HBr
+
Mg(OH)2 →
MgBr2
+
H2O
2)
PbBr2
+
HCI
HBr
+
PbCl2
3)
CoBru
+
CaSO4 →
CaBr2
+
Coz(504)3
4)
C4H12
+
O2
CO2
+
H2O
5)
B2O3
+
H2O
H3BO3
6)
H₂O
H₂
+
O2
7)
C₂H4
+
O2
CO2
+
H2O
8)
+
Mg
+
Fe₂O₃ →
Mgo
Fe
9)
+
H3PO4
+
Ca(OH)2 →
Ca3(PO4)2
H2O
10)
Cl2
+
KBT
+
KCI
Brz
11)
+
H3ASO4
As2O5
H₂O

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

a polar bond is formed when electrons are shared unevenly between atoms

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.