01 Consider the following reversible reaction
CO(g) + 2H2(g) → CH2OH(g)
What is the equilibrium constant expression for the given system?
Keq =
[CO[H212
[CH3OH)
[CH3OH)
Keq =
[CO][H2)2
Keq =
[COJH2)
[СН, ОН]
[CH, OH)
[COLH2]
Ο Κeg
Keq -

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2