How much heat is released as 5.00G of PB cool from 75.0° C to 25.0° C

32.25 J

Explanation:

Heat, H = ?

Mass, m = 5g = 5 / 1000 = 0.005 Kg

Initial Temperature = 75.0° C

Final Temperature = 25.0° C

Temperature change, ΔT = Final - Initial = 50° C

Specific heat capacity of lead, C = 129 (J/kg°C)

The relationship between these quantities is given by the equation

H = mCΔT

H = 0.005 * 129 * 50

H = 32.25 J

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.