g You are given a 1.25 gram mixture of calcium nitrate and calcium chloride. You dissolve this mixture in 200.0 mL of water and add an excess of 0.300 M silver nitrate. You collect and dry the white precipitate which forms and find it has a mass of 0.535 grams. Calculate the percent calcium chloride by mass in the original mixture.

16.51%

Explanation:

The reaction that takes place is

Meaning that the white precipitate that formed is AgCl. Now we convert 0.535 g of AgCl into moles, using its molar mass:

Then we convert 0.00373 moles of AgCl into moles of CaCl₂, using the stoichiometric coefficients:

We convert moles of CaCl₂ into grams, using its molar mass:

Finally we calculate the percent of CaCl₂ by mass in the original mixture:

c. 75.7

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