In the reaction shown, what is the mole ratio that would be used to determine the number of moles of H2 that would be produced when 3.5 moles of AIC13 are produced? 2Al(s) + 6HCl(aq) + 3H2 2AlCl3(aq) O 2 mol Al divided by 3 mol HCI O 3 mol H2 divided by 2 mol AICI: 3.5 mol AlCl3 divided by 3 mol of H2 O 3 mol AlCl3 divided by 2 mol H2 O 2 mol AlCl3 divided by 3 mol of H2​