6HCl(aq) + 2A1) -
3H2(g) + 2AlCl3(aq)
1. How many moles of hydrogen are produced from 1.20 moles of aluminum?

1.80 moles of will be produced 1.20 moles of aluminium.

Explanation:

To calculate the moles :

The balanced chemical reaction is:

According to stoichiometry :

2 moles of produce = 3 moles of

Thus 1.20 moles of will produce=  of

Thus 1.80 moles of will be produced 1.20 moles of aluminium.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year