A compound was analyzed in a lab to determine its empirical formula. Decomposition of the compound at a standard temperature and pressure produced
9.00g carbon, 16.8L hydrogen, and 2.80L oxygen. The molar mass of the compound
is 116g/mol. What is its molecular formula?
please show work

Explanation:

The answers are 5C, 1N, and 5H. The empirical formula is C5H5N, which has a molar mass of 79.10 g/mol. To find the actual molecular formula, divide 240, the molar mass of the compound, by 79.10 to obtain 3. So the formula is three times the empirical formula, or C15H15N3.

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in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.