Question 4 L2.2
Boyle's law is

P. V1 = P2V2 A balloon has an initial volume of 355 L and an initial pressure of 234 kPa.

The volume is lowered to a final value of 227 L Use Boyle's Law to calculate the final pressure.
Round to two decimal points and do not use units.

Question 5
L2.3

The ideal gas law equation is

PV=nRT

How many moles of gas are in closed container with a pressure of 400 kpa, volume of 10L and a temperature of 450 K?

use 8.31 L * kpa/K * mol for R​

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.

you did not give any options thus this is the best answer i can give to you with this little information you have given

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