A solution contains 6 mg isopropanol dissolved in 2 kg H2O. The isopropanol concentration is? a. 3% isopropanol.
b.3 M isopropanol.
c.3 m isopropanol.
d. 3 ppm isopropanol.

Option D. 3 ppm isopropanol.

Explanation:

From the question given above, the following data were obtained:

Mass of isopropanol = 6 mg

Mass of water = 2 Kg

Isopropanol concentration =?

Concentration = mass isopropanol / mass of water

Isopropanol concentration = 6 mg / 2 kg

Isopropanol concentration = 3 mg/Kg

Next, we shall convert 3 mg/Kg to ppm. This can be obtained as follow:

Recall:

1 mg/Kg = 1 ppm

Therefore,

3 mg/Kg = 3 ppm

Thus, the isopropanol concentration is 3 ppm.

43.452

step-by-step explanation:

284 times .153 = 43.452