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Chemistry, 18.03.2021 02:00 yeeyee69

7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =

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7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =...
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