Chemistry, 12.03.2021 21:40 lwattsstudent
M H20 × c H20 × (ΔT h20) = -(m Cu × c Cu × (ΔT Cu))
100g × 4.184 (j/g °C) × (23.52 °C - 20 °C) = -(50g × c cu× (23.52 °C - 100 °C))
how would i set this up find specific heat capasity (c) of copper? (Cu)
Answers: 3
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M H20 × c H20 × (ΔT h20) = -(m Cu × c Cu × (ΔT Cu))
100g × 4.184 (j/g °C) × (23.52 °C - 20 °C) = -(...
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