Nickel carbonyl decomposes to form nickel and carbon monoxide, like this: Ni(CO)4(g) → Ni(s)+ 4CO(g)

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel carbonyl, nickel, and carbon monoxide at equilibrium has the following composition:

compound amount
Ni(CO)4 0.597g
Ni 12.7g
CO 1.98g

Required:
Calculate the value of the equilibrium constant for this reaction.

Explanation:

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In this case, according to the given chemical reaction, it is possible to set up the equilibrium expression as shown below:

Since the nickel product is solid and is not included. It means that the concentrations at equilibrium of CO and Ni(CO)₄ are:

Thus, there equilibrium constant for the reaction turns out to be:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :