Calculate the enthalpy change for the reaction: C6H4(OH)2(aq) + H2O2(aq) <—> C6H4O2(aq) + 2H2O(l) given the following data:

C6H4(OH)2(aq)-->C6H4O2(aq)+H2(g) H= +174.4 kJ

H2O(g)-->H2O(l) H= -43.8 kJ

H2(g)+1/2O2(g)-->H2O(g) H= -241 kJ

H2(g)+O2(g)-->H2O2(aq) H= -191.2 kJ