Calculate the quantitative concentration of HCl in the solution if in the reaction of 500 cm3 the solution with AgNO3 produces 0.7 g of AgCl AgNO3 + HCl > AgCl + HNO3

9.77x10⁻³M HCl

Explanation:

Assuming the solution of AgNO₃ is in excess:

Based on the chemical equation:

AgNO₃ + HCl → AgCl + HNO₃

We must find the moles of AgCl that will be produced. With the moles and knowing 1 mole of AgCl is produced from 1 mole of HCl we can find the moles of HCl and its concentration as follows:

Moles AgCl -Molar mass: 143.32g/mol-:

0.7g AgCl * (1mol / 143.32g) = 4.88x10⁻³moles AgCl = Moles HCl

As the volume of the solution is 500cm³ = 0.500L, the concentration of HCl is:

4.88x10⁻³moles HCl / 0.500L =