How many L are required to make 3.5 M hydrochloric acid using 1.1 moles?

0.31 L

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Chemistry

Atomic Structure

Moles

Aqueous Solutions

Molarity = moles of solute / liters of solution

Equilibrium - Acid/Base

Strong AcidsWeak AcidsWriting AcidsExplanation:

Step 1: Define

[Given] 3.5 M HCl

[Given] 1.1 moles

[Solve] Liters solution

Step 2: Solve

Substitute in variables [Molarity]:                                                                  [Solution] Cross-Multiply [Equality Property]:                                                [Solution] Divide:                                                                                            

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.314286 L ≈ 0.31 L

It’s the energy source of stars

Temperature and pressure