Calculate the molecular formula of a compound whose molar mass in 184.5 g/mol and has an empirical formula of CCIN (note Cl- Chlorine).

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

bcde is the incorrect answer it is a

catya that's not even a b or c