If 8.82 grams of Aluminum reacts, how many grams of AlCl3 will be produced?

Hey there! :

Molar mass:

Al = 26.9815 g/mol

AlCl₃ = 133.3405 g/mol

Reaction stochemistry ,calculates the mass of AlCl3 produced

2 Al + 3 Cl₂ =  2 AlCl₃

2 * 26.9815 g Al  2 *  133.3405 g AlCl₃

8.82 g Al  ( mass of AlC₃ )

mass of AlCl₃  =  ( 8.82 * 2 * 133.3405 ) /  ( 2 * 26.9815 )

mass of AlCl₃ = 2352.12642 / 53.963

mass of AlCl₃ = 43.58 g of AlCl₃

Hope this helps!

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer