What is the systematic name of the following compound? \text{Mn}_3 (\text {PO}_4)_2Mn
3
​
(PO
4
​
)
2
​

Manganese (II) Phosphate

Explanation:

Mn3(PO4)2 is the compound given in this question. Manganese is the metal and hence it will come first in the name. Along with the name of metal it is essential to determine the valency of the metals based on the compound structure.

Here 2 PO4 attaches with 3 Mn

Valence of PO4 is -3

So the total electrons contributed by PO4 is 3*2 = 6

Now Mn has 3 atoms in the compound. Thus, per atom the valency must be 2 in order to satisfy -6 charge of PO4

Thus, valency of Mn is 2

So, the name will be

Manganese (II) Phosphate.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.